2x^2-25x=10

Solution for 2x^2-25x=10 equation:

2x^2-25x=10

We move all terms to the left:

2x^2-25x-(10)=0

a = 2; b = -25; c = -10;
Δ = b2-4ac
Δ = -252-4·2·(-10)
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{705}}{2*2}=\frac{25-\sqrt{705}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{705}}{2*2}=\frac{25+\sqrt{705}}{4}
$